PHP - 假时获取布尔以回显假
以下代码不打印任何内容:
The following code doesn't print out anything:
$bool_val = (bool)false;
echo $bool_val;
但是下面的代码打印出 1:
But the following code prints 1:
$bool_val = (bool)true;
echo $bool_val;
当 $bool_val 为 false 时,有没有比添加 0 或 false 更好的方法来打印code>if 语句?
Is there a better way to print 0 or false when $bool_val is false than adding an if statement?
推荐答案
echo $bool_val ? 'true' : 'false';
或者如果你只想在它为假时输出:
Or if you only want output when it's false:
echo !$bool_val ? 'false' : '';
相关文章