如何为可重用的 Django 应用程序进行迁移?
问题描述
我正在制作一个没有项目的可重用 Django 应用程序.这是目录结构:
I am making a reusable Django app without a project. This is the directory structure:
/
/myapp/
/myapp/models.py
/myapp/migrations/
/myapp/migrations/__init__.py
当我运行 django-admin makemigrations 时出现以下错误:
When I run django-admin makemigrations I get the following error:
django.core.exceptions.ImproperlyConfigured: Requested setting DEFAULT_INDEX_TABLESPACE, but settings are not configured. You must either define the environment variable DJANGO_SETTINGS_MODULE or call settings.configure() before accessing settings.
显然，这是因为我没有配置设置模块，因为这是一个可重复使用的应用程序.但是，我仍然想使用我的应用程序进行迁移.我怎样才能制作它们?
Obviously, this is because I don't have a settings module configured, because this is a reusable app. However, I would still like to ship migrations with my app. How can I make them?
解决方案
其实你不需要有项目，你只需要设置文件和脚本，运行迁移创建.设置必须包含以下内容(最少):
Actually, you don't need to have project, all you need is settings file and script, that runs migrations creation. Settings must contain folowing (minimum):
# test_settings.py
DEBUG = True
SECRET_KEY = 'fake-key'
INSTALLED_APPS = [
'django.contrib.admin',
'django.contrib.auth',
'django.contrib.contenttypes',
'your_app'
]
进行迁移的脚本应该如下所示:
And the script, that makes migrations should look like this:
# make_migrations.py
import os
import sys
if __name__ == "__main__":
os.environ.setdefault("DJANGO_SETTINGS_MODULE", "test_settings")
from django.core.management import execute_from_command_line
args = sys.argv + ["makemigrations", "your_app"]
execute_from_command_line(args)
你应该通过 python make_migrations.py 运行它.希望它可以帮助某人！
and you should run it by python make_migrations.py. Hope it helps someone!