为什么 ={} 初始化不适用于元组?
对我来说，pair 只是 tuple 的特例，但以下让我感到惊讶:
To me a pair is just special case of a tuple, but following surprises me:
pair<int, int> p1(1, 2); // ok
tuple<int, int> t1(1, 2); // ok
pair<int, int> p2={1, 2}; // ok
tuple<int, int> t2={1, 2}; // compile error
为什么我们用{}来初始化tuple会有区别?
Why there is difference when we use {} to initialize tuple?
我什至尝试了 g++ -std=c++1y 但仍然有错误:
I tried even g++ -std=c++1y but still has error:
a.cc: In function 'int main()':
a.cc:9:29: error: converting to 'std::tuple<int, int>' from initializer list would use explicit constructor 'constexpr std::tuple<_T1, _T2>::tuple(_U1&&, _U2&&) [with _U1 = int; _U2 = int; <template-parameter-2-3> = void; _T1 = int; _T2 = int]'
tuple<int, int> t2={1, 2};
^
推荐答案
<你试图调用的代码>元组构造函数是explicit，所以copy-list-initialization 将失败.对应的 pair 构造函数 不是 显式.
The tuple constructor you're trying to call is explicit, so copy-list-initialization will fail. The corresponding pair constructor is not explicit.
将您的代码更改为
tuple<int, int> t2{1, 2};
它会编译.
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