确定字符串是否仅包含字母数字字符(或空格)
我正在编写一个函数来确定字符串是否仅包含字母数字字符和空格.我正在有效地测试它是否匹配正则表达式 ^[[:alnum:] ]+$ 但不使用正则表达式.这是我目前所拥有的:
I am writing a function that determines whether a string contains only alphanumeric characters and spaces. I am effectively testing whether it matches the regular expression ^[[:alnum:] ]+$ but without using regular expressions. This is what I have so far:
#include <algorithm>
static inline bool is_not_alnum_space(char c)
{
return !(isalpha(c) || isdigit(c) || (c == ' '));
}
bool string_is_valid(const std::string &str)
{
return find_if(str.begin(), str.end(), is_not_alnum_space) == str.end();
}
有没有更好的解决方案,或者更多的C++"如何做到这一点?
Is there a better solution, or a “more C++” way to do this?
推荐答案
我觉得不错,但是你可以用 isalnum(c) 代替 isalpha 和 isdigit.
Looks good to me, but you can use isalnum(c) instead of isalpha and isdigit.
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